A25 newton force applied on an object moves it 50 meters. the angle between the force and displacement is 40.0°. what is the value of work being done on the object?
0 joules
9.6 × 102 joules
1.2 × 103 joules
-9.6 × 102 joules
-1.2 × 103 joules

The right option is 9.6 x 10² joules.

Explanation:

Given a 25 newton force applied on an object with a 40° angle, that moves it 50 meters, you have to employ the formule for work that states that W = F·d. As you can see in the attach 25 newton is the magnitude of the resultant force, so we have to find the magnitude of this force in the horizontal plane (the same plane of the displacement).  

Fx = F · cos (40°) ⇒ Fh = 19.15 newton.

⇒ W = F · d ⇒ W = Fx · d ⇒ W = 957.5 Joules (9.57 x 10² Joules)

Approximating W = 9.6 x 10² Joules.

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

answer: mole of the gas

answer: mole of the gasexplanation: