For a caffeinated drink with a caffeine mass percent of 0.51% and a density of 1.00 g/ml, how many ml of the drink would be required to reach an ld50 of 170 mg/kg body mass if the person weighed 171 lb?

2,585.47 mL of the drink would be required to reach an LD-50 for 171 lb person.

Explanation:

LD-50 of caffeine = 170 mg/kg body mass

Mass of the person = 171 lb = 77.56 kg

1 lb = 0.453592 kg

Lethal dose for person with mass 171 lb = 77.56 kg × 170 mg/kg =13,185.92 mg

13,185.92 mg = 13.18592 g

(1 mg = 0.001 g)

Percentage of caffeine in drink = 0.51 %

Mass of drink = M

M = 2,585.47 g

Volume of the drink = V

Density of the drink = D = 1.00 g/mL

2,585.47 mL of the drink would be required to reach an LD-50 for 171 lb person.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

pie chart because it is in percents ( % )