Chemistry, 29.01.2020 00:52 waterdrop026
The reaction ab(aq)→a(g)+b(g) is second order in ab and has a rate constant of 0.0164 m −1 ⋅ s −1 at 25.0 ∘ c . a reaction vessel initially contains 250.0 ml of 0.104 m ab which is allowed to react to form the gaseous product. the product is collected over water at 25.0 ∘ c . part a how much time is required to produce 142.0 ml of the products at a barometric pressure of 707.3 mmhg . (the vapor pressure of water at this temperature is 23.8 mmhg .)
Answers: 1
![v=k[AB]^2](/tpl/images/0479/4220/bde1b.png)
. In the statement, we obtain that ![[AB]=0.104~M](/tpl/images/0479/4220/4f567.png)
and, at 25 ºC, 
. Then:![v=k[AB]^2\\\\ v=0.0164\cdot0.104^2\\\\ v=0.0164\cdot0.010816\\\\ v\approx0.000177=1.77\times10^{-4}~mol/s](/tpl/images/0479/4220/68b4c.png)
. Hence: 
.
. Furthermore, since the ratio of AB to A and to B is 1:1, 
.![v=\dfrac{|\Delta[AB]|}{\Delta t}=\dfrac{1}{\Delta t}\cdot\dfrac{|\Delta n_{AB}|}{V}=\dfrac{1}{\Delta t}\cdot\dfrac{|\Delta n_A||}{250~mL}\\\\ 1.77\cdot10^{-4}=\dfrac{1}{\Delta t}\cdot\dfrac{0.0026~mol}{0.25~L}\\\\ \Delta t=\dfrac{0.0026}{0.25\cdot1.77\cdot10^{-4}}\\\\ \boxed{\Delta t\approx58.76~s}](/tpl/images/0479/4220/8e656.png)
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