Calculate the molar solubility of copper(ii) arsenate (cu3(aso4)2) in water. use 7.6 x 10-36 as the solubility product constant of cu3(aso4)2.
9.1 x 10-4 m
3.4 x 10-2 m
3.7 x 10-8 m
8.7 x 10-2 m

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

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