Chemistry, 14.11.2019 00:31 11needhelp11

Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 m hcl) that is required to make 500.0 milliliters of a 6.0 m hcl?

12.0 m * 0.500 l = 6.0 m * v2

12.0 m * 6.0 m = 0.500 l * v2

12.0 m * v1 = 6.0 m * 0.500 l

6.0 m * v1 = 12.0 m * 0.500 l

(12.0 m + 6.0 m) = 0.500 l * v2

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Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid...