In view of bohrs explanation of the link between emission spectra and electron transitions, answer more fully the question, what does each line represent in the emission and absorption spectra of an incandescent gas? i have a general idea but i cant think of enough to meet the word requirement.

According to Bohr's explanation the lines of an emission or absorption spectra of an incandescent gas are representative of the energy radiated from the hydrogen atom. When an electron moves from one energy level to another lower level it releases, or radiates, the differences in energy between the two separate energy levels. This released energy, as mentioned, is displayed as a bright-line. Each of these individual lines also represent a different color of light, and therefore a different wavelength and frequency. That's what I have so far, but it still isn't long enough.

mechanics (greek   is that area of science concerned with the behaviour of physical bodies when subjected to forces or displacements, and the subsequent effects of the bodies on their environment. the scientific discipline has its origins in ancient greece with the writings of aristotle and archimedes[1][2][3] (see history of classical mechanics and timeline of classical mechanics). during the early modern period, scientists such as galileo, kepler, and newton laid the foundation for what is now known as classical mechanics. it is a branch of classical physics that deals with particles that are either at rest or are moving with velocities significantly less than the speed of light. it can also be defined as a branch of science which deals with the motion of and forces on objects. the field is yet less widely understood in terms of quantum theory.

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml