How many grams of nacl are required to make 500.0 ml of a 1.500 m solution?

43.875 grams of NaCl are required to make 500.0 ml of a 1.500 M solution.

Explanation:

Moles of NaCl = n

Volume of NaCl solution = 500.0 mL = 0.500 L

Molarity of the NaCl solution  = 1.500 M

Mass of 0.75 moles of NaCl:

0.75 mol × 58.5 g/mol=43.875 g

43.875 grams of NaCl are required to make 500.0 ml of a 1.500 M solution.

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