Achemist has 2.0 mol of methanol (ch₃oh). the molar mass of methanol is 32.0 g/mol. what is the mass, in grams, of the sample?
16
30
32
64

64

Explanation:

Mole of a compound = mass of a compound / molar mass of a compound

Mass of a compound = mole of a compound x molar mass of a compound

Given,

Mole of methanol = 2 mol

Molar mass of methanol = 32 g/mol

Mass of methanol = Mole of methanol x Molar mass of methanol  

                               = 2 mol x 32 g/mol = 64 g

Therefore, the mass, in grams, of the sample = 64

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

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