There are 342 g of sucrose in 1.00 mol of sucrose. what is the molar concentration (molarity) of a solution containing 171 g sucrose in 1.25l solution?

For the answer to the question above, use these formulas in solving your problem and as a guide.
 
MM = 342 (g/mol) 

171 (g) / 342(g/mol) = x mol of sucrose 
x moles of sucrose/ 1.25 L =  Molarity of soultion 

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