Use vsepr theory to predict bond angles in the following covalently bonded molecules. explain your predictions.
a. methane
b. ammonia
c. water

Bond angle for methane is 109.5°,Bond angle for ammonia is 107° and Bond angle for water is 104.5°

:

where, V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

a. Methane:

In the given molecule, carbon is the central atom and there are 4 Hydrogens as monovalent atoms.

The number of electrons is 4 that means the hybridization will be and geometry of the molecule will be tetrahedral.The bond angle for terahedral geometry is 109.5°.

b. Ammonia:

In the given molecule, nitrogen is the central atom and there are 3 Hydrogens as monovalent atoms.

The number of electrons is 4 that means the hybridization will be and geometry of the molecule will be pyramidal as there are three bond pairs and one lone pair.The bond angle for pyramidal geometry is 107°.the bond angle reduces due to lone pair bond pair repulsions.

c. water :

In the given molecule, oxygen is the central atom and there are 2 Hydrogens as monovalent atoms.

The number of electrons is 4 that means the hybridization will be and geometry of the molecule will be bent as there are two bond pairs and two lone pairs.The bond angle for pyramidal geometry is 104.5°.The bond angle reduces further due to greater lone pair-lone pair repulsions.

the answer is 0.42 is that is an option. this question provides no info