If you react 59.54 g of S and 78 g of HNO3, how many grams of NO2 can you theoretically produce?
S + 6 HNO3 + H2SO4 + 6 NO2 + 2 H2O

56.94759 grams of NO2

Explanation:

Stoichiometric Equation:

1 S + 6 HNO3 → 1 H2SO4 + 6 NO2 + 2 H2O.

This is so you can create ratios between each compound in the reaction, and identify the limiting and excess reactants to determine exactly how much can be produced?

The coefficients or molecular quantity of each compound in the balanced equation represents the amount of moles.

To figure out how much can be produced, you have to convert 59.54 g of S into moles of S and 78 g of HNO3 into moles of HNO3.

A reference such as a periodic table can be very helpful as it has the atomic mass of each element which is the mass with respect to 1 mol of that element.