It takes 2 g of chlorine to sanitize 1,000,000g of water. How much chlorine will it take to sanitize a 40,000-gallon pool? ( 1 gallon =3.7L; the density of water is 1.0g/ml ) Show your work

0.1g (Gallon) of chlorine

Explanation:

Formula

1 gallon = 3.7L; the density of water is 1.0g/ml

Given

2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water

Solve

If 2g (gallon) chlorine = 1,000,000g (gallon)

∴, ? chlorine = 40,000

The First step; set up an equation

1000000/2 = 40000/?

The Next step; divide 1 million to 2

1000000 ÷ 2 = 500000

Then, divide the result by 40000

40000 ÷ 500000 = 0.08

In the nearest unit that is 0.1

Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.

296

Explanation:

1 gallon = 3.7 L

40,000 gallon

= 40,000 × 3.7

= 148,000 L

1 g = 1 / 1000 L

1,000,000 g

= 1,000,000 / 1000

= 1,000 L

Let x be the amount of chlorine that will it take to sanitize a 40,000-gallon pool.

2 : 1,000 : : x : 148,000

2 / 1,000 = x / 148,000

x × 1,000 = 2 × 148,000

x = ( 2 × 148,000 ) / 1,000

= 2 × 148

x = 296 g

Therefore,

296 g of chlorine will it take to sanitize a 40,000-gallon pool.

( I solved using maths )

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.