How many grams of water, H 2 O , is given o when 62.1 g of propane, C 3 H 8 , burns?

101.62 grams of water is given o when 62.1 g of propane burns.

Explanation:

Propane gas (C₃H₈) burns with oxygen gas and products carbon dioxide gas and liquid water. The balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By stoichiometry, the following amounts of moles of each compound participate in the reaction:

Being the molar mass of each compound:

By stoichiometry, the following mass quantities of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 44 grams of propane produces 72 grams of water, 62.1 grams of propane how much mass of water does it produce?

mass of water= 101.62 grams

101.62 grams of water is given o when 62.1 g of propane burns.

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explanation:

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons