You are performing a reaction involving the collection of a gas at SATP. If 5.00 g of magnesium is added to 100.0 cm3 of 0.100 mol dm−3 HCl, determine the volume of hydrogen gas that will be collected at SATP.

The volume of hydrogen produced is 0.122 L

Explanation:

To calculate the moles :

The balanced chemical equation is:

According to stoichiometry :

2 moles of require = 1 mole of

Thus 0.01 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 2 moles of give = 1 mole of

Thus 0.01 moles of give =  of

According to ideal gas equation:

P = pressure of gas = 1.0 atm  (SATP)

V = Volume of gas = ?  

n = number of moles = 0.005

R = gas constant =

T =temperature = (SATP)

Thus volume of hydrogen produced is 0.122 L

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be