29 mols of na2So4 is how many grams

Explanation:

4118.2

Explanation:

Given: 29 moles of na²

To find: In grams.

Solution: Wrong

If 1 na² is 142 grams, then 29 grams will be found if a set of fraction has been set up;

Let be the variable

Cross multiply

Correct Solution

Multiply 29 by 142 = 4118

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

your answer would be a. 12.5 kg