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Chemistry, 15.04.2021 02:50 miargaree1823

A. The rate of the reaction 2N03(9) = N204(9) is given by the rate law below: Rate = K[NO2)2
What would the rate of the reaction be under the following conditions?
rate constant = 1.8 x 103 (L/mol)/s
[NO2] = 0.007 M

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A. The rate of the reaction 2N03(9) = N204(9) is given by the rate law below: Rate = K[NO2)2
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