Chemistry, 13.04.2021 16:40 shandrablue6896

In a separate location, take notes from the sources you’ve identified. The notes will provide details for your paper. While taking notes, you may want to use these reading strategies. Use these sources if you find them helpful: Using your notes, compare the features of analog and digital signals in the table provided. Include one to three points for each feature and type of signal.

In a separate location, take notes from the sources you’ve identified. The notes will provide detai

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Answer from: jemseidle8889

Should we write the analog or digital?

Answer from: zitterkoph

Here is every answer for analog and digital (in order)

Analog:

Signal Shape: Smooth and continuousNumerical Values for Signal Measurements: Analog signals represent one continuous variable as the result of another continuous time-based variable. They are capable of outputting continuous information with a theoretically infinite number of possible values.Amount of Data that can be transmitted: analog circuits can conduct only fairly low-speed data communications. The maximum data rate over an analog facility is 33.6K bps when there are analog loops at either end. With 56K bps modems, only one end of the loop can be analog. The other end of the connection has to be digital. Energy requirements: light, sound, temperature, position, and pressurePrivacy and security (ability of the signal to be encoded in a secret code): not encryptedClarity of Signal: noise affects clarity and quality, noise is amplified, amplified noise causes more random information in the signal, signal bandwidth is low

Digital (in order):

Signal shape: stepping, square, and discreteNumerical Values for Signal Measurements: digital communication methods transmit a complete measured value, in other words both a numeric value and a unit of measurement Amount of data that can be transmitted: First of all, it is theoretically possible to transmit digital signals directly. Unfortunately when we use capacitors and inductors (energy storage devices) to match the impedance from the transmitter to the air (low impedance transistor say 5 ohms to 388 ohms (air)) these components introduce a bandwidth limiting match. Since all impulse functions have infinite bandwidth (transmitting a 1 and a zero) the bandwidth of the transceiver must be multi octave in order to have any reasonable efficiency. Systems engineers simplify the problem by introducing direct sequence modulation where a carrier is modulated 0/180 degrees dependent on the data rate.Energy requirements: voltage, accoustic pressure, and magnetization of a magnetic storage mediaPrivacy and security: encryptedClarity of signal: noise is lower in amplitude, electronics can ignore the noise, quality of signal is maintained, signal is high

Explanation:

I did mine in bullet points, hopefully this helped!

Answer from: Quest

by cartels in other countries, shipped by air, mail, or land. i cant really see your answer choices : /

Answer from: Quest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.