In water, HCl forms two ions and hence i=2. In benzene, however, HCl does not form any ions and i=1. Pure benzene boils at 80.1°C. Imagine that you have 1000g of water and 1000g of benzene in separate beakers. Into each beaker you add 250g of HCl. What will be the new boiling points of benzene and water?

The correct answer would be 1. precipitation

☆ionisation energy increases across a period from na -> ar☆ionisation energy decreases down a group from li -> fr☆ionic radius decreases across a period from na -> cl☆ionic radius increases down a groupfrom f -> ii hope it clarifies your doubts

Answer (b) supersaturation;

Answer is: hydrogen is being oxidized.chemical reaction: co₂ + h₂ → co + h₂o.oxidation half reaction: h₂ → 2h⁺ + 2e⁻.reduction half reaction: c⁺⁴ + 2e⁻ → c⁺².oxidation is increase of oxidation number, hydrogen change oxidation number from neutral charge (in molecule of hydrogen) to oxidation number +1 (in water).