What is the pOH of a solution that has an H+=7.7x10^-7 M

Explanation:

Step 1

The question is based on the concept of PH and pOH calculations.

pH is defined as negative logarithmic of hydronium Ion concentration.

while pOH is defined as negative logarithmic of hydroxide ion concentration of the solution.

Step 2

[H+] = 7.7*10-7  M  

pH = -log[H+]  

    = -log ( 7.7*10-7 )

     = 6.12

Step 3

pOH = 14 - pH

   = 14 - 6.11

  = 7.89

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa