And a 40N Torce in a southeriy direction? 4. A car works harder to accelerate from 0 to 10km/hr than it does to maintain a 10km/hr speed. Why is this? A. b/c
static friction is harder to overcome than kinetic or rolling friction. B. b/c static friction is easier to overcome than
kinetic or rolling friction. C. b/c static friction is harder to overcome than potential energy. D. b/c static friction is
easier to overcome than gravity.

C.

Explanation: because potential energy is the starting point before it moves. nothing has to be done.

stupid i wont let you get a chance

explanation:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.