A gas of certain mass occupies a volume of 650cm^3 under a pressure of 750 mm Hg. Calculate the pressure under which the volume of gas will be reduced by 10 percent of its original volume.​

7500 mmHg

Explanation:

From the question,

Applying Boyles Law,

PV = P'V' Equation 1

Where P = original pressure, P' = final pressure, V = Original Volume, V' = Final Volume.

make P' The subject of the equation

P' = PV/V' Equation 2

Given: P = 650 cm³, P = 750 mmHg, V' = (650×10/100) = 65 cm³ (Reduced by 10 percent of it original volume)

Substitute these values into equation 2

P' = (650×750)/65

P' = 7500 mmHg

58750.08068 is the answer i think