A 0.114 g Fe sample required 18.7 ml EDTA solution. Find the % Fe2O3( Fw=159.6882 g/mol) in the sample. If 25.0 ml EDTA required 15 ml of 1.1*10 ppm CaCl, (Fw = 110.985 g/mol)

for points guys

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph