If a total of 23.5 mol of NaHCO3 and 6.5 mol of C6H2O7 react, how many moles of CO2 and NazC6H3O7 will be produced?(Show all your work)
3NaHCO3 (aq) + CH3O+ (aq) --> 3C02 (9) + 3H O(s) + Na3C6H307 (aq)

it's c (engineer's do their work with mechanical stuff not on any living being)

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

i believe the answer is three water molecules