Consider the following reaction: 4P + 502 - P4010
The percent yield of P4010 when 6.20 g of phosphorus burns in
excess oxygen is 67.0 %.What is the actual yield of P4010?
(Molar mass of P = 31.0 g/mol, molar mass of P4010 = 284
g/mol) (Round your answer 3 significant figures e. g. 5.62)

grams​

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