CsHo + 502 → 3CO2 + 4H2O
Answer the following questions about the equation shown.
1. How many atoms of Carbon are in the reactants (total)?
2. How many atoms of Hydrogen are in the reactants (total)?
3. How many TOTAL atoms of Oxygen are in the reactant?
4. How many TOTAL atoms of Carbon are in the product?
5. How many TOTAL atoms of Oxygen are in the product?
6. How many atoms of Hydrogen are in the product?
7. Does the number of atoms of each element on the reactant side match that of the product side?

I do not know the Answer I'm just trying to get my point

Explanation:

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explanation:

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally