g Consider a pure sample of a radioactive isotope with a mass number of (46 A). If the sample has mass of (25.0 B) micrograms and the isotope has a half-life of (4.50 C)x106 years, determine the decay rate for the sample. Give your answer in decays/second and with 3 significant figures.

This question is incomplete, the complete question is;

g Consider a pure sample of a radioactive isotope with a mass number of (46 + A). If the sample has mass of (25.0 + B) micrograms and the isotope has a half-life of (4.50 + C)x10⁶ years,

determine the decay rate for the sample. Give your answer in decays/second and with 3 significant figures.

A = 1, B = 1, C = 11.

the decay rate for the sample is 469,625.898 decay/s    

Explanation:

Given the data in the question;

= ( 4.50 + C ) × 10⁶ years  

C = 11

= ( 4.50 + 11 ) × 10⁶ years

= 15.50 × 10⁶ years

= 15.50 × 10⁶ × 365 × 24 × 60 × 60  

λ = 0.693 /

so

λ = 0.693 / ( 15.50 × 10⁶ × 365 × 24 × 60 × 60  )

also

N = ( 25.0 + B )

B = 1

N = ( 25.0 + 1 )

N = 26 × 10⁻⁶

isotope with a mass number of ( 46.0 + A ) , A=1

= ( 46.0 + 1 ) = 47

N = 26 × 10⁻⁶( 1/47 )( 1 / 1.67 × 10⁻²⁷ ) =  3.31252 × 10²⁰  

R = λN

so

R = (0.693 / ( 15.50 × 10⁶ × 365 × 24 × 60 × 60  )) × (3.31252 × 10²⁰)

R = 1.41773 × 10⁻¹⁵ × (3.31252 × 10²⁰)

R = 469,625.898 decay/s    

Therefore, the decay rate for the sample is 469,625.898 decay/s    

answer: i dont know the answer but this might

explanation:

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water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.