One of the few xenon compounds that form is cesium xenon heptafluoride (csxef7). how many moles of csxef7 can be produced from the reaction of 11.0 mol cesium fluoride with 11.5 mol xenon hexafluoride?
csf(s) + xef6(s) csxef7(s)

11 moles

Explanation:

As can be seen from the balanced chemical reaction,

1 mole of CsF reacts with 1 mole of

Thus 11 moles of CsF react with 11 mole of

Thus CsF is the limiting reagent as it limits the formation of products and is the excess reagent as (11.5-11)=0.5 moles are in excess.

As  1 mole of CsF produces= 1 mole of

11 moles of CsF will produce= of

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