3. At what temperature in Celsius will 9.8 grams of NH3 will exert a pressure of 98.3 KPa at a volume of 21.0 Liters?

156.78 °C

Explanation:

First we convert 9.8 grams of NH₃ into moles, using its molar mass:

Then we can use the PV=nRT formula to calculate the temperature, where:

We input the data:

And solve for T:

Finally we convert 429.94 K to °C:

58750.08068 is the answer i think