A mixture of0.159 moles of C is reacted with 0.117 moles of O2 in a sealed, 10.0 L-vessel at 500.0 K, producing a mixture of CO and CO2. The limiting reagent of the below reaction is carbon. For 0.159 moles of carbon, determine the amounts of products (both the CO and CO2) formed in this reaction. Also, determine the amount of O2 remaining and the mole fraction of CO when the reaction is complete. 3C(s)+2O2(g)â2CO(g)+CO2(g). 

the answer is 303.15 or 303

6.4 cm (max) - 25 cm (min)

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.