1N2 + 3H2 ---> 2NH3 How many moles of N2 gas present in 50.0 grams
of nitrogen gas in the above reaction ? g->mol
N- 14

5.36 moles

Explanation:

From the given chemical equation, we see that one mole of nitrogen gas reacts with 3 moles of hydrogen gas in terms of mass.

Molar mass of hydrogen gas ; H2 = 2.016 g/mol

Molar mass of nitrogen gas; N2 = 28.01 g/mol

Thus;

28.01 grams of nitrogen gas requires 3 moles of hydrogen gas

Thus;

28.01 grams of nitrogen gas requires 3 moles of hydrogen gas

Therefore, 50 g of nitrogen gas will require; (50 × 3)/28.01 = 5.36 moles

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