Propane(C_3H_8 Delta H_f = -104.63 kJ/mol) reacts with oxygen to produce carbon dioxide (CO_2 Delta H_f = -393.5 kJ/mol) and water (H_2O DeltaH_f = -241.82 kJ/mol) According to the equation Down below C_3H_8 + 3O_2 -> 3CO_2 + 4H_2O.

Why is the Enthalpy of Combustion of C_3H_8 in the reaction that I showed above?

Any help would be greatly appreciated. (at this point i dont care if you show any work at all.)
(i just want help with this one thing and I dont really use points so i have put a total of 300 points into just this question)
i have also included the question in the form that it is meant to be shown in.
and
Please please PLEASE dont post scams like here is the link to this suspicions zip file or anything like that. that has happen on the last two tiems i asked for this one question

2b2t

explanation:

2b2t

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.

the objects have the same charge is correct.

nathan lee