Using the information in the table to the right, calculate the average atomic mass of strontium. Report to two decimal places. 45
amu
A 3 column table with 4 rows titled Strontium. Column 1 is labeled Isotope with entries Upper S r-84, Upper S r-86, Upper S r-87, Upper S r-88. Column 2 is labeled Mass (a m u) with entries 83.913428, 85.909273, 86.908902, 87.905625. Column 3 is labeled Abundance (percent) with entries 0.56, 9.86, 7, 82.58.

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g