Calculate and compare the freezing points of the following aqueous solutions: 0.0500 m CaCl, and 0.0500 m KCI. The freezing point depression constant, Ry, for water is 1.86 "C/mol.
A. The freezing points of both 0.050 m KC and 0.050 m CaCl, are the same namely, 0.186°C
B. The freezing point of 0.050 m KCl is - 0.279°C. The freezing point of 0.050 m Caci, is-0.186°C,
which is not as low as that of a potassium chloride solution of the same molality.
C. The freezing point of 0.050 m CoC, is 0.279°C. The freezing point of 0.050 m Klis-0.186"C.
which is not as low as that of a calcium chloride solution of the same molality.
D. The freezing points of both 0.050 m KCl and 0.050 m Cact, are the same namely,-0.279°C.

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.

answer:

technetium is the most reactive. this is followed by silver. the least reactive out of these three elements is strontium.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.