2. X
You put 0.53 g of barium in a crucible weighing 22.45g. After reacting it with
chlorine the final compound and crucible has a mass of 23.25g.
a. How many moles of barium did you react?
and
b. How many grams of chlorine reacted with the barium?
C.
How many moles of chlorine reacted?
d. What is the mole ratio? (moles chlorine / moles barium)
e. What is the empirical formula

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole