A tower built of Iron is 500 meter tall. What is the change in height (m) if it is exposed to 25 0 Celsius during summer and at 1.00 Celsius during winter. α iron = 1.2 x 10-5/ Celsius

-0.144 m

Explanation:

From the question,

α = Δh/(h₁Δt) Equation 1

Where α = coefficient of linear expansivity of iron, Δh = change in height, h₁ = initial height, Δt = change in temperature.

make Δh the subject of the equation

Δh = α(h₁Δt) Equation 2

Given: α = 1.2×10⁻⁵/°C, h₁ = 500 m,

Δt = (t₂-t₁) Where t₂ and t₁ = Final and initial temperature respectively.

Δt = (1-25) = -24 °C

Substitute these values into equation 2

Δh =  1.2×10⁻⁵[500×(-24)]

Δh = 1.2×10⁻⁵(-12000)

Δh = -0.144 m