In a mixing unit at your plant, you mix 40 moles/min of an equimolar mixture of benzene (1) 1 2-propanol (2) at 298.15 K with 80 moles/min of pure benzene at 298.15 K. If you desire to keep the resulting mixture at 298.15 K, what is the heat load on this system

It conforms what ever surface its in.

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

Hi + naoh -> h2o + nal

Answersublimation;