what is the percent of sulfur in sulfuric acid H2SO4? round your answer to the tenths place (1 decimal point)​

32.7%

Explanation:

To calculate the percentage by mass of an element in a compound, the following procedure is employed:

- Find the atomic mass of the element

- Find the molar mass of the compound

- Divide the atomic mass of the element by the molar mass of the compound and multiply by 100

Mathematically; this is denoted by:

Mass % of Sulphur = (Atomic mass of S/Molar mass of H2SO4) × 100

Atomic mass of S = 32g/lol

Molar mass of H2SO4 = 1(2) + 32 + 16(4) = 2 + 32 + 64

= 98g/mol

Hence,

% mass of S = 32/98 × 100

= 0.3265 × 100

= 32.65

= 32.7 (1 d.p)

Therefore, the percent of sulfur in sulfuric acid (H2SO4) is 32.7%

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

= enthaply

= energy of products

= energy of reactants

as , thus comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.