Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 15.7 g of hydrochloric acid is mixed with 27. g of sodium hydroxide. Calculate the maximum mass of sodium chloride that could be produced by the chemical reaction.

25.155 gram

Explanation:

HCl(aq.) + NaOH(aq.) ⇒ NaCl + H2O

According the above equation equal number of moles of reactant are producing same number of moles of products.

Now, no. mole of HCl = 15.7/(1+35.5) = 0.43 moles

no. of moles of NaOH = 27/(23+16+1) = 0.675 moles

Since  the  amount  of  sodium  hydroxide  exceeds  the  amount  of  hydrochloric  acid,  the maximum amount of each substance participating in the reaction is HClν ν  0.43 moles .Therefore, the maximum amount of NaCl  that can be produced is as follow

= (23+35.5)×0.43 = 25.155 gram

explanation:

i think option no d is the correct answer

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