An unknown solid has a specific heat capacity of 0.727 J/gC. If a 12.3 grams sample is heated and increases in temperature from 22.4C to 62.1C, calculate how much heat was absorbed? You must show your work. I'm a little lost

355Joules

Explanation:

The amount of heat absorbed can be calculated using the formula:

Q = m × c × ∆T

Where;

Q = amount of heat absorbed in joules

m = mass of substance in grams

c = specific heat capacity of solid (0.727 J/g°C)

∆T = final temperature - initial temperature (°C)

According to the information provided in this question;

Q = ?

m = 12.3g

∆T = 62.1°C - 22.4°C = 39.7°C

c = 0.727 J/g°C

Using Q = m × c × ∆T

Q = 12.3 × 0.727 × 39.7

Q = 355.001

Q = 355Joules

Hence, 355J of heat was absorbed

the correct answer is:

a. formation of precipitation

give me abc and i will get it for u.