If the He H e injected into the abdomen produces a pressure of 22 mmHg m m H g and a volume of 2.7 L L at 31 ∘C ∘ C , how many grams of He H e were used?

1280.27 g

Explanation:

Pressure = 22 mmHg / 760 = 0.0289 atm (Converting to atm by dividing by 760)

Volume = 2.7 L

Temperature = 31 ∘C + 273 = 304 K

Mass = ?

Using the ideal gas equation;

PV = nRT

n = RT / PV = 0.0821 * 304 / ( 0.0289 * 2.7)

n = 319.86 mol

Mass = Number of moles * Molar mass

Mass = 319.86  * 4.002602

Mass = 1280.27 g

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.