The boiling point of water is elevated when 125 g of ethylene glycol (C₂H₆O₂) is dissolved in 1200 g of water. What is the new boiling point of water? Kb for water is 0.52 C°/m.

100.87°C

Explanation:

This is about elevation of boiling point, one of the colligative properties.

Formula is:

Boiling T° of solution - Boiling T° of pure solvent = Kb . m . i

Kb is the boiling constant.

m means molality (mol/kg of solvent)

i = numbers of ions dissolved.

Our solute is C₂H₆O₂. As it is an organic compound, no ion is generated, so i = 1.

We determine moles of solute: 125 g . 1mol /62g = 2.02 moles.

We determine molality = 2.02 mol / 1.2 kg → 1.68 m.

Boiling T° of solution - 100°C = 0.52°C/m .  1.68m  . 1

Boiling T° of solution = 0.52°C/m .  1.68m  . 1 + 100°C →  100.87 °C

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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