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Chemistry, 31.08.2019 12:50 homework1911

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1. a gas occupies 30 l at 760 mm hg. what is its volume at 350 mm hg?
p1*v1 = p2*v2
760 mm hg *30 l = 350 mm hg * v2
v2 = 22800 mm hg*l/350 mm hg
v2 = about 65.14 l
2. a gas occupies 500 ml at 1 atm. what is its pressure if the volume becomes 1500 ml?
p1*v1 = p2*v2
1 atm*500 ml = p2*1500 ml
500 atm*ml/1500 ml = p2
p2 = 1/3 atm
3. if a gas occupies 250 ml at 25°c, what will its volume be at 57°c?
25°c + 273 = 298°k; 57°c + 273 = 330°k
v1/t1 = v2/t2
250 ml/298°k = v2/330°k
0.84 ml/k*330°k = v2
v2 = about 276.85 ml
4. what was the original temperature of a 2 l sample of gas if it initially had the volume 5 l at 27°c?
27°c + 273 = 298°k
v1/t1 = v2/t2
5 l/298°k = 2 l/t2
2 l/(0.017 l/k)= t2
t2 = 119.2°k = -153.8°c
5. at what pressure would 100 ml of a gas be found if it began at 500 ml at 2.5 atm?
p1*v1 = p2*v2
2.5 atm*500 ml = p2*100 ml
125 atm*ml/100 ml = p2
p2 = 1.25 atm
6. what is the volume of a gas at 275 mm hg if it occupied 750 ml at 1000 mm hg?
p1*v1 = p2*v2
1000 mm hg*750 ml = 275 mm hg*v2
75 mm hg*ml/275 mm hg = v2
v2 = about 2727. 27 ml
7. a gas occupies 60 l at 250°k and 1 atm. what is its volume at 250°c and 1.5 atm?
250°c + 273 = 523°k
p1*v1/t1 = p2*v2/t2
1 atm*60 l/250°k = 1.5 atm*v2/523°k
0.24 (atm*l/k)*523°k = 1.5 atm*v2
125.52 (atm*l)/1.5 atm = v2
v2 = 83.68 l
8. what is the final temperature in celsius of a gas occupying 3.25 l at 750 mm hg if it occupied 2250 ml at 37°c and 600 mm hg?
37°c + 273 = 310°k; 2250 ml = 2.25 l
p1*v1/t1 = p2*v2/t2
600 mm hg*2.25 l/310°k = 750 mm hg*3.25 l/t2
2437.35 mm hg*l/ (4.35 mm hg*l/k) = t2
t2 = 559.69°k
t2 = about 286.69°c

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