a container of gas has a pressure of 1.45 atm at a temperature of 52 degrees celsius, if the pressure increases to 4.2 atm what would be the final temperature of the volume is held constant?

941 K (668°C)

Explanation:

We have the following data:

Initial pressure : P1 = 1.45 atm

Initial temperature: T1 = 52°C + 273 = 325 K

Final pressure: P2 = 4.2 atm

Final temperature: T2 = ?

The relation between pressure and temperature for a gas at constant volume is given by Gay-Lussac's law:

P1/T1 = P2/T2

That means that the pressure is directly proportional to the absolute temperature (in K). So, we calculate T2 from the equation:

T2 = P2 x T1/P1 = 4.2 atm x (325 K/1.45 atm) = 941 K

Therefore, the final temperature would be 941 K (668°C). This is consistent with the law, that states that if the pressure increase, the temperature will be increased.  

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.