If it takes 38.70 cm^3 of 1.90M NaOH to neutralize 10.30cm^3 of H2SO4 in a battery. What is the concentration of the H2SO4?

3.57 M

Explanation:

The reaction that takes place is:

First we calculate how many NaOH moles reacted, using the given concentration and volume:

Then we convert NaOH moles into H₂SO₄ moles, using the stoichiometric coefficients:

Finally we calculate the concentration of H₂SO₄:

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

there all right good

explanation: