The velocity of a car goes from 0 m/s to 60 m/s in a forward direction. what is the best explanation for this change?

question 10 options:

when the speed was 0 m/s, the forces acting on the car were unbalanced. when the forces became balanced, the car started to move.

when the velocity was 0 m/s, all the forces acting on the car were balanced. the velocity changed because at least one unbalanced force is acting on the car.

when the inertia was constant, the speed was 0 m/s. the speed changed because the inertia of the car increased.

the force of gravity on all sides was equal at 0 m/s. the velocity of the car increased because the force of gravity on the back of the car increased.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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