Chemistry, 20.03.2021 19:20 jeanniebyrd54

Hi please help quick! A second order reaction has a rate constant of 0.0805 M^-1s^-1 at 1110 K and a rate constant of 0.0910 M^-1s^-1 at 1210 K. Calculate the activation energy for the reaction in kJ/mol.

R = 8.314 J mol^-1 K^-1

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Hi please help quick! A second order reaction has a rate constant of 0.0805 M^-1s^-1 at 1110 K and...