Using the equation below, find how many moles of water can be produced from 1.85 moles of Al(OH)3, given excess HF. Round to the nearest 0.01 and include units and substance (the formula!) in your answer. 3 HF + Al(OH)3 --> AlF3 + 3 H2O

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

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atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

the answer is d.) potassium