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Chemistry, 19.03.2021 03:10 Tyrant4life

HNO3(aq) + KOH
(aq)
→ H2O (1) + KNO3 (99) + 55.31 kJ
when 400.0 mL of 0.0500 mol/L. HNO3(aq) is added to an unknown volume of 0.0500 mol/L
KOH(aq), the temperature increases from 18,67°C to 19.00°C. Assuming that both solutions
have a specific heat capacity of 4.19 J/g °C and a density of 1.000 g/mL, what volume of
KOH(aq) was used?

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Answers: 3

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You know the right answer?
HNO3(aq) + KOH
(aq)
→ H2O (1) + KNO3 (99) + 55.31 kJ
when 400.0 mL of 0.0500 mol/...

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