What pressure is required to reduce 63 mL of a gas at standard conditions to 20 mL at the temperature of 24◦C? Answer in units of atm, please.

3.43atm

Explanation:

Using the combined gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the provided information in this question,

P1 = 1 atm (standard pressure)

P2 = ?

V1 = 63mL

V2 = 20mL

T1 = 273 K (standard temperature)

T2 = 24°C = 273 + 24 = 297K

Using P1V1/T1 = P2V2/T2

1 × 63/273 = P2 × 20/297

63/273 = 20P2/297

Cross multiply

297 × 63 = 273 × 20P2

18711 = 5460P2

P2 = 18711/5460

P2 = 3.426

P2 = 3.43atm

passed in september 1935, these laws are known as nuremberg laws.   they forbid jews from marrying but not directly forced them to divorce aryans. what is most noticeable is the fact that the jews were defranchised, meaning by this that they were not expected to have any civil rights, including the right to vote. the right answer is deprived of the right to vote.