What is the molarity of a solution that contains 2.14 moles (CH3)2SO in 2.00 L solution?

1.07 M

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Molarity = moles of solute / liters of solutionExplanation:

Step 1: Define

[Given] 2.14 moles (CH₃)₂SO

[Given] 2.00 L

[Solve] Molarity

Step 2: Solve

Substitute in variables [Molarity]:                                                                    x M = 2.14 moles (CH₃)₂SO / 2.00 L solution[Molarity] Divide:                                                                                               x = 1.07 M

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I’m not sure what your trying to say here.. can you clarify again?